Question

A TV that weighs 300 N is at rest on the floor. If the pressure exerted by the TV on the
floor is 25,000 Pa, over what area is the box in contact with the floor?

Answer 1

Proper question:

A TV that weighs 300 N is at rest on the floor. If the pressure exerted by the TV on the floor is 25,000 Pa, over what area is the box in contact with the floor?

Given that:

• Force = 300 N
• Pressure = 25,000 Pa

To determine:

• Area

Solution:

• Area = 83.3 m $\:$

Using concept:

• Pressure formula

Using formula:

• Pressure = Force/Area

Required solution:

»»» Pressure = Force/Area

»»» 25000 = 300/Area

»»» 25000/300 = Area

»»» 250/3 = Area

»»» Area = 83.3 m

Answer 2

★ Question :-

A TV that weighs 300 N is at rest on the floor. If the pressure exerted by the TV on the floor is 25,000 Pa , over what area is the box in contact with the floor?

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★ Answer :-

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✠ Given :-

• Force = 300 N
• Pressure = 25,000 Pa

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✠ To Find :-

• The Area [ A ] = ?

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✠ Solution :-

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∓ We have to calculate the Area on which Force is acting .

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✪ Pressure = Force / Area

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➠ 25,000 = 300 / Area

➠ Area = 25,000 / 300

➠ Area = 250 / 3

➠ Area = 83.3 m

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★ Hence :-

• The Area = 83.3 m

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