a TV tower stands vertically on a bank of a Canal from a point on the other bank directly opposite the tower the angle of elevation of the top of the tower is 60° from. 10 m away from this point on the same bank the angle of elevation of the top of the tower is 30° find the height of the tower and the width of the canal
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Let the height of the tower be h and width of the canal be w.
tan 60=h/w=√3
h=w√3 equation 1
tan 30=h/(w+10)=1/√3
w+10=h√3 equation 2
put the value of h from equation 1 in equation 2
w+10=w√3×√3=3w
2w=10
w=5
put this value of w in equation 1, you will get
h=5√3
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