. A TV tower stands vertically on a
of a canal. From a point on the other
bank directly opposite the tower, the
angle of elevation of the top of the
tower is 60°. From another point 20 m
away from this point on the line joing
this point to the foot of the tower, the
angle of elevation of the top of the
tower is 30° (see Fig. 9.12). Find the
height of the tower and the width of
the canal.
D
From the top of a 7 m high building,
Answers
Answer:
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Answer:
A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is 60
∘
. From another point 20 m away from this point on the line joing this point to the foot of the tower, the angle of elevation of the top of the tower is 30
ANSWER
In the figure, let AB be the tower and AC be the canal. C is the point on the other side of the canal directly opposite the tower.
Let AB=h,CA=x and CD=20
From right △BAC.
cot60
o
=x/h
1/
3
=x/h
x=h/
3
....(1)
From right △BAD:
cot30
o
=AD/AB
3
=(x+20)/h
x=h
3
−20....(2)
h=10
3
From (1): x=(10
3
)/
3
=10
Therefore, the width of the canal is 10 m and height of the canal is 10
3
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