Math, asked by aanchal3053, 1 year ago

A TV was bought at a price of Rs 21000 after 1 year the value of the TV was depreciated by 5% find the value of the TV after 1 year


siddhantsingh20: this is solved by the simple interest FORMULA. SI -- CP × RATE × TIME / 100
siddhantsingh20: you will get intrest, then subtract the intrest to cost price. You will get your answer

Answers

Answered by dhanur1000
13

Cost price of tv is = 21000

After one year value decreased by 5%

So ATQ

Current value = C.P -5%of C.P

=21000 -5/100×21000

=19950



sree1974pccuvq: thanks
Answered by BrainlySamaira
24

Answer:

{ \huge \bf{ \mid{ \overline{ \underline{\red {A\green n\purple s\pink wer}}}} \mid}}

\small\underline\textsf{\red{ the value of TV after one Year}=\underline{19,950}}

\small\underline\frak{Given}

\sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: pricipal = rs.21000 \\\sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:reduction = 5\% \: of \: 21000 \: per \: year

\small\star\underline\frak{to \:find :- }

\small\underline\textsf{the value of TV after one Year}

\huge\underline\textsf{Explantion:-}

\boxed{\boxed{\underline{\sf{\frac{21000 \times 5 \times 1}{100}  = 1050}}}} \\

\sf value \: at \: the \: end \: of \: 1 \: year \\\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 21000 - 1050 = 19,950

 \rule{300}{2}

\huge\underline\frak{Alternately:- }

\small\underline\textsf{we \: may \: directly \: get \: this \: as \: follows}

\sf value \: at \: the \: end \: of \: 1 \: year = \boxed{(1 -  \frac{5}{100})}

\boxed{\boxed{\boxed{\sf 21000 \times  \frac{19}{20}}}}  \\

\star\sf 19,950

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