A twi digit no in which Ten's digit (greater than unit's digit), is obtained by multiplying the sum of digits by 7 and then adding 3 or by multiplying difference of digits by 20 and then substracting 7. We want to find the number
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Let the digits be x and y and the number is 10x+y
It is given
x=7(x+y)+3
6x+7y+3=0 equation 1
x=20(x-y)-7
19x-20y-7=0 equation 2
Multiply equation 1 by 20 and equation 2 by 7 and then add, you will get
120x+60+133x-49=0
253x+11=0. This is absurd. I think equations 1 and 2 are not framed correctly. Language is not clear.
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