A two digit is such that the product of the digits is 18.when 63 is substracted from the number,the digits interchange their places.
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3×6=18
hence 3and 6 are numbers because they interchange their places
hence 3and 6 are numbers because they interchange their places
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✰ The required number is 92.
✰ product of digits = 18
✰ when 63 is substracted from the number ,the digits interchange their places.
✰ we need to find the number.
- Let the tens place digit be x
- Let the unit place digit be y
Then,
xy = 18
y = 18/x..............(1)
and,
(10x + y)- 63 = 10y + x
9x - 9y = 63
Dividing both side by 9.
x - y = 7.............(2)
Putting value of y from (i) into (ii).
x² - 18 = 7x
x² - 7x - 18 = 0
x² - 9x + 2x - 18 = 0
x(x - 9)+ 2( x - 9) = 0
(x -9)(x+2) = 0
x = 9 or x = -2
x = 9 [a digital cannot be negative].
putting x = 9 in equation (i) ,
we get, y = 2
Thus ,
the tens digit is 9 and units digit is 2.
Hence , the required number is 92.
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