Question

A two-digit natural number is such that the product of its digits is 12. When 3 is added to this number, the digits interchange their places. Find the number
pls tell fast​

Answer 1

Let a digit at unit’s place be x and at ten’s place by y .

Then according to problem

Required no. = 10y + x

On interchanging the digits

Number formed = 10x + y

xy = 12

∴ x = 12/y

10y + x + 36 = 10x + y

10y + x – 10x – y = - 36

9y – 9x = - 36

9(y – x) = - 36

y – x = - 36/9

y – x = - 4

On substituting value of x = 12/y

y - 12/y = - 4

y2 – 12/y = - 4

y2 + 4y – 12 = 0

y2 + 6y – 2y – 12 = 0

y(y + 6) – 2(y + 6) = 0

( y + 6)(y – 2) = 0

y = - 6, 2

When y = 2

x = 12/2 = 6

Required no. = 10y + x

= 10 × 2 + 6

= 20 + 6

= 26

mark as brainliest dude. , 26 is your answer. and your question is not 3, its 36 right? hope its right

Answer 2

Answer:

bijnar

Step-by-step explanation:

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