Question

A two digit no. and the number with digits interchanged add up to 143. In the
given number the digit in unit's place is 3 more than the digit in the ten's
place. Find the original number.
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Answer 1

Step-by-step explanation:

the digit at tens place=143-x thus the original nois=10×[134-x)+X=1340-10+X=1340_9x on interchanging the no the digit at ones place become (1340-x) new no=10x+(1340-x)=9x+1340 new no_original no=[1340_9x) (1340+9x) =13