A two digit no is 3 more than 4 times the sum of its digits .If 18 is added to this no ,the sum is equal to the number obtained by interchanging the digits . find the number ( linear equation in two variable )
Answers
Answered by
1
10x+y=3+4×(x+y)
10x+y=3+4x+4y
6x-3y=3
2x-y=1
10x+y+18=10y+x
9x-9y=-18
x-y=-2
-(2x-y=1)
-x=-3
x=3
6-y=1
-y=-5
y=5
no.==53
plzzz mark brainliest.......
Answered by
2
Let the digits be x and y.
Thus, number=10x+y
Now,
(10x+y) - 4(x+y)= 3.....(i)
and
(10x+y)+ 18=10y+x.....(ii)
Solving (i)
10x+y-4x-4y=3
or,6x-3y=3
or,2x-y=1....(1)
Solving (ii)
10x+y-10y-x=-18
or, 9y-9x=18
or,y-x=2...(2)
(1)+(2)
2x-y+y-x=1+2
or,x=3
Thus, y=x+2 (from (2))
y=5
Therefore the number= 10x+y=10x3+5=35
please mark me as brainliest
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