a two digit no. is 3more than 4times the sum of its digit.if 18is add to the no.the digits are reverse.find the no.
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Two digit number = 10x + y
According to the question
10x + y = 4(x + y) + 3
10x + y = 4x + 4y + 3
6x - 3y = 3
2x - y = 1. -(1)
10x + y + 18 = 10y + x
9x - 9y = -18
x - y = -2. -(2)
Solving both equation simultaneously
2x - y = 1
x - y = -2
(-) (+) (+)
-----------------
x = 3
Putting the value of x on 1st equation
2x - y = 1
(2*3) - y = 1
y = 5
Two digit number = 10x + y
= (10*3) + 5
=35
According to the question
10x + y = 4(x + y) + 3
10x + y = 4x + 4y + 3
6x - 3y = 3
2x - y = 1. -(1)
10x + y + 18 = 10y + x
9x - 9y = -18
x - y = -2. -(2)
Solving both equation simultaneously
2x - y = 1
x - y = -2
(-) (+) (+)
-----------------
x = 3
Putting the value of x on 1st equation
2x - y = 1
(2*3) - y = 1
y = 5
Two digit number = 10x + y
= (10*3) + 5
=35
sunita7777:
original no.is 10y+x
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