A two digit no. is 4 times the sum of its digits and twice the product of the digits. find the no.
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Let the two digit number be xy having tens digit as x and unit digit as y which is simply written as 10x+y
Two digit number=10x+y and sum of its digits=x+y
Given, two digit number is four times the sum of its digits.
10x+y=4(x+y)
10x+y=4x+4y
10x-4x=4y-y
6x=3y
2x=y =>y=2x -------> (1)
Product of the digits=xy
Also, the two digit number is twice the product of its digits
10x+y=2xy
substitute eqn (1) i.e., y=2x in the above eqn.
10x+2x=2x(2x)
12x=4x*x
12=4x
x=12/4=3=>x=3
Substitute x=3 in eqn. (1)
y=2x=>y=2(3)=6=>y=6
Therefore, x=3 and y=6
Hence the two digit number is xy=36.
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