Question

a two digit no. is 4times the sum and 3times the product of its digit. find the no.

Answer 1

Let the digit at tens place be x and the digit at tens place be y.

Therefore, the original number = 10x + y.

Given that two digit number is 4 times the sum.

= > 10x + y = 4(x + y)

= > 10x + y = 4x + 4y

= > 6x = 3y

= > 2x = y    ------ (1)

Given that it is three times the product of its digit.

= > 10x + y = 2xy

= > 10x + 2x = 2xy

= > 12x = 2xy

= > y = 6.

Substitute y = 6 in (1), we get

= > 2x = y

= > 2x = 6

= > x = 3.

Hence, the number = 10x + y

= > 10(3) + 6

= > 36.

Therefore, the original number = 36.

Hope this helps!