Question

A two digit no is four more than 6 times the sum of its digits if 18 is subtracted from the no digits are reversed find the number

Answer 1

solution;

let the required two digit no be 10x+y

now,

as per the 1st condition:

10x+y=6(x+y)+4-----------1

as per the 2nd condition:

10x+y-18=10y+x

or,10x-x+y-10y=18

or,9x-9y=18

or,x-y=2

or,x=y+2------------2

putting the value of x in eqn 1:

10(y+2)+y=6(y+2+y)+4

or,11y+20=12y+16

or,12y-11y=20-16

so,y=4 i.e.x=4+2=6

so,the required no is:

10x+y

=10.6+4

=64

Answer 2

Answer:

Step-by-step explanation:

Brainly.in

What is your question?

Secondary SchoolMath 5+3 pts

A two digit number is 4 more than 6 times the sum of its digits. If 18 is subtracted from the number, the digits are reversed. Find the numbers

Brainly User

Let x = ones digit

and y = tens digit

then from "a two digit number is 4 more than six times the sum of its digits":

x + 10y = 6(x+y)+4

x + 10y = 6x+6y+4

10y = 5x+6y+4

4y = 5x+4

.

and, from "if 18 is subtracted from the number,the digits are reversed.find the number"

x+10y -18 = y+10x

10y -18 = y+9x

9y -18 = 9x

y -2 = x

.

substitute the above into:

4y = 5x+4

4y = 5(y-2)+4

4y = 5y-10+4

4y = 5y-6

4y+6 = 5y

6 = y

.

substitute above into:

4y = 5x+4

4(6) = 5x+4

24 = 5x+4

20 = 5x

4 = x

.

The number is 64