Question

A two digit no is four times the sum of its digits and twice the product of its digits. Find the number. ​

Answer 1

Answer:

36

Given:

A two digit number is four times the sum of its digit

And twice the product of its digit

To find:The number

Solution:-

Let the tens digits be 10x and unit digit be y

Then,the number is 10x+y

A/Q the digit is four times the sum of digit

10x+y=4(x+y)

10x+y=4x+4y

6x=3y

y=2x

And twice the product of it's digit

10x+y=2xy

As y=2x

10x+2x=2×x×2x

12x=4x^2

3=x

Then,y=2x

=2×3

=6

---------

The number=4(x+y)

=4(3+6)

=4×9

=36

Answer 2

Answer:

The number is 36 .

Step-by-step explanation:

Let,

the ones digit of the number be x

& tens digit be y

hence , the number would be x + 10y .

___________________[Assume]

--------------------------------------------------

Since, the 2 digit number is 4 times the sum of its digits.

Therefore,

x + 10y = 4(x + y)

_______________________[Given]

=> x + 10y = 4x + 4y

=> 3x = 6y

=> x = 2y ......(I)

Also,

the 2 digit number is twice the product of its digits.

Therefore,

x + 10y = 2xy ......(II)

_______________________[Given]

Putting the value of x in equation (II), we get

2y + 10y = 2(2y)(y)

=> 12y = 4y²

=> y² = 3y

=> y = 3

Substituting the value of y in eqn (I),

=> x = 2(3)

=> x = 6

____________________________

Hence, the number is x + 10y = 6 + 10(3)

= 6 + 30

= 36

_______________________[Answer]