Question

A two digit no. is four times the sum of the digit . it is also equal to 3 times the product of digit.
find the no.

Answer 1

Hey,. Let the two digit number be 10(x+y),
10(x+y)=4(x+y)
6x+6y=0->equation one

Now,
10(x+y)=3xy
10x+10y-3xy=0->equation two
So, now solve the two equations and get the answer.

Hope this helps you buddy!!
GOOD NIGHT :-):-)

Answer 2

hey... here's ur solution !!
let unit digit and ten's digit of the two digit number be x and y.

therefore, number is 10y + x
according to question,

= 10y + x = 4( y + x)
= 10y + x = 4y + 4x
= 10y - 4y = 4x -x

= 6y = 3x
= 2y = x................................. (1)

Also,

10y + x = 3xy.......................... (2)
= 10y + 2y = 3( 2y) y

= 12 y = 6y²

= 6y² - 12y = 0
6y ( y -2 ) = 0

y = 0 or y =2.


rejecting y = O as the no. can not be zero.

x = 4

therefore,
required no. is 24


Hope it might be helpful !!