A two digit no. Is such that the digit is added is 12. When 9 is added to the no. , the digit interchange their places. Determine the no.
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Let the number's tens place to be x and ones place to be y.
then no. will be 10x+y
According to question- x+y=12(equation-1)
and 10x+y+9=10y+x(no.resrved)
=> 10x+y-10y-x=-9
=> 9x-9y=-9
=>9(x-y)=-9
=> x-y=-1(equation 2)
Now putting the value of equation 1 and equation 2 together.
=x+y=12
=x-y=-1
=2x=11
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