A two digit no is such that the product of the digit is 8 when 18 is added to the no the digit are reversed the no is
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Here is your answer,
Let the ten's and unit digit be x and 8/x respectively.
Then , ( 10x + 8/x ) + 18 = 10 x 8/x + x
➡10x^2 + 8 + 18x = 80 + x^2
➡9x^2 + 18x - 72 = 0
➡x^2 + 2x - 8 = 0
➡( x + 4 ) ( x - 2 ) = 0
X = 2
Hope it helps you!
Here is your answer,
Let the ten's and unit digit be x and 8/x respectively.
Then , ( 10x + 8/x ) + 18 = 10 x 8/x + x
➡10x^2 + 8 + 18x = 80 + x^2
➡9x^2 + 18x - 72 = 0
➡x^2 + 2x - 8 = 0
➡( x + 4 ) ( x - 2 ) = 0
X = 2
Hope it helps you!
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