Question

A two digit no is such that the product of the digit is 8 when 18 is added to the no the digit are reversed the no is

Answer 1

Hey

Here is your answer,

Let the ten's and unit digit be x and 8/x respectively.

Then , ( 10x + 8/x ) + 18 = 10 x 8/x + x

➡10x^2 + 8 + 18x = 80 + x^2

➡9x^2 + 18x - 72 = 0

➡x^2 + 2x - 8 = 0

➡( x + 4 ) ( x - 2 ) = 0

X = 2

Hope it helps you!