a two digit no. is such that the sum of the digits is 6 .if the digit of the no. are reversed the new no. gets diminshed by 18 find the origanal no.
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Let the tens place digit be a
And Unit place digit be b
Number = 10a +b
Reversed number = 10b +a
Sum of digits = a+b
=> a+b = 6
=> a = 6-b --------(1)
Original no. - Reversed no. = 18
=> 10a +b - 10b - a = 18
=> 9a - 9b = 18
=> a - b = 2
=> 6-b-b = 2
=> - 2b = 2-6
=> 2b = 4
=> b = 4
On putting the value of b in equation 1, we get
a= 6-4 = 2
Required number = 24
And Unit place digit be b
Number = 10a +b
Reversed number = 10b +a
Sum of digits = a+b
=> a+b = 6
=> a = 6-b --------(1)
Original no. - Reversed no. = 18
=> 10a +b - 10b - a = 18
=> 9a - 9b = 18
=> a - b = 2
=> 6-b-b = 2
=> - 2b = 2-6
=> 2b = 4
=> b = 4
On putting the value of b in equation 1, we get
a= 6-4 = 2
Required number = 24
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