A two digit no such that the product of its digit is 24. If 8 added to the digit are reversed. Find the no.
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Let x = the 10's digit
Let y = the units
then
10x + y = the number
"The product of digit of two digit number is 24."
x * y = 24
"If 18 is added to the number, digits are reversed."
10x + y + 18 = 10y + x
10x - x + 18 = 10y - y
9x + 18 = 9y
simplify, divide by 9. results
x + 2 = y
Using the 1st equation, replace y with (x+2)
x(x+2) = 24
x^2 + 2x - 24 = 0; our old friend, the quadratic equation!
Factors to
(x+6)(x-4) = 0
the positive solution
x = 4
then
y = 4 + 2
y = 6
as x=4 y=6
46 is the number
:) Hope this helps!!!!!
Let y = the units
then
10x + y = the number
"The product of digit of two digit number is 24."
x * y = 24
"If 18 is added to the number, digits are reversed."
10x + y + 18 = 10y + x
10x - x + 18 = 10y - y
9x + 18 = 9y
simplify, divide by 9. results
x + 2 = y
Using the 1st equation, replace y with (x+2)
x(x+2) = 24
x^2 + 2x - 24 = 0; our old friend, the quadratic equation!
Factors to
(x+6)(x-4) = 0
the positive solution
x = 4
then
y = 4 + 2
y = 6
as x=4 y=6
46 is the number
:) Hope this helps!!!!!
nitthesh7:
if u find it most helpful mark it as brainliest
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