Math, asked by Twet7963, 1 year ago

A two digit number ab is 60% of x. The two-digit number formed by reversing the digits of ab is 60% more than x. Find x.

Answers

Answered by Anonymous
11

Solution :-

According to the question,

10a + b = 60% of x

=> 10a + b = 0.6x _______(i)

10b + a = x + 60% of x

=> 10b + a = x + 0.6x

=> 10b + a = 1.6x _______(ii)

Subtract equation (i) from (ii) we get,

(10b + a) - (10a + b) = 1.6x - 0.6x

=> 10b + a - 10a - b = x

=> 9b - 9a = x

=> x = 9(b - a)

Here, x should be multiple of 9.

10a + b = 0.6x => 10a + b = 3x/5

this implies that x should also multiple of 5 Or, x should be a multiple of 45.

So, ab = 60% of 45 = 27 and ba = 72

Answer : x = 45

Similar questions