A two digit number and the number with digits interchanged add up to
143. In the given number the digit in unit's place is 3 more than the
digit in the ten's place. Find the original number.
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let 2digit no. be 10x+y
A two digit number and the number with digits interchanged add up to 143
=> x+y =143÷11=13
and given y=x+3
y-x = 3 ---A
y+x =13 ----B
y= 8
x=5
no. is 10*5+8 =58
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