A two digit number and the number with digits interchanged add up to 143 .In the given number the digit in unit place is 3 more than the digit ten s places. Find the original number .
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xy be the number
(10x+y)+(10y+x)=143 》x+y=13
also from given
y-x=3
solving the above 2 equations we will get y=8
and x=5
original number=58
(10x+y)+(10y+x)=143 》x+y=13
also from given
y-x=3
solving the above 2 equations we will get y=8
and x=5
original number=58
Answered by
51
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