a two digit number and the number with digits interchanged add up to 143 in the given number the digit in unit's place is 3 more than the digit in the ten place find the original number
Answers
Answered by
40
I hope this will help you.......
Attachments:
UtkarshPant:
Please mark it as brainliest
Answered by
5
let 10x be the ten's place and y be the unit place its the original number
so if they interchange it will become 10y+x it's the interchange number
x=10+y. given
so 10(10+y)+y + 10y+10+y= 143
after solving it we get 110+22y=143
22y=143-110
y=3/2
so substitute the y value and get x then form the x and y in the original number
so if they interchange it will become 10y+x it's the interchange number
x=10+y. given
so 10(10+y)+y + 10y+10+y= 143
after solving it we get 110+22y=143
22y=143-110
y=3/2
so substitute the y value and get x then form the x and y in the original number
Similar questions