Question

A two digit number and the number with digits interchanged add up to 143. In the given number the digit in unit's place is 3 more than the digit in the ten's place. find the original number ​

Answer 1

Answer:

58

Step-by-step explanation:

Let the number be 10x+y

10x+y+10y+x=143

11x+11y=143

11(x+y)=143

x+y=143/11

x+y=13

y-x=03

y+x=13

2y=16

y=16/2

y=8

x+y=13

x+8=13

x=13-8

x=5

The number is 10x+y

10(5)+8

50+8

58