Question

. A two digit number and the number with digits is interchanged add up to 143. In the given number the digit in unit's place is 3 more than the digit in ten's place Find the original number Complete the following activity Number Digit in Digit in unit's place ten's Place riginal Number Х у 10x + y​

Answer 1

Step-by-step explanation:

So, let the original no. be ten's digit of the number be x then the one's digit will be (x+3) then the original no = 10x + (x+3)

= by interchanging we get 10(x+3) + x

so A/Q = 10x +(x+3) + 10(x+3) +x = 143

= 10x + x+3 + 10x + 30 + x = 143

= 22x + 33 = 143

= 22x = 110

= x = 110/22

= x = 5

so the original no = 10x+ (x+3) = 10X 5 + 5+3 = 50+8 = 58 Ans

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