a two digit number becomes five sixth of itself when its digits are reversed . the two digit differ by 1 . what is the original number
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Answered by
296
let the units place digit be x and tens place digit be y
therefore the original number is 10y + x and new number is 10x + y
therefore:
50y+5x = 60x+6y
44y = 55x
4y - 5x = 0 ___ (i)
y-x = 1 ___ (ii)
(ii) × 4:
4y-4x = 4
(i) - (ii):
(4y-5x) - (4y-4x) = 0-4
-5x-4x = -4
-x = -4
x = 1
y = x + 1 = 5
therefore original number is 54
therefore the original number is 10y + x and new number is 10x + y
therefore:
50y+5x = 60x+6y
44y = 55x
4y - 5x = 0 ___ (i)
y-x = 1 ___ (ii)
(ii) × 4:
4y-4x = 4
(i) - (ii):
(4y-5x) - (4y-4x) = 0-4
-5x-4x = -4
-x = -4
x = 1
y = x + 1 = 5
therefore original number is 54
rohanharolikar:
original number is greater that new number
Answered by
124
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