A two digit number becomes four seventh of itself when the position of its digit are interchanged. The difference between the both digits is 3. What is the number
Answers
EXPLANATION.
- GIVEN
A two digit number becomes four seventh
of itself when the position of it's digit are
interchanging.
The difference between the both digit is = 3
TO FIND THE NUMBER.
According to the question,
Let the unit place be = y
Let the tens place be = x
original number = 10x + y
reversing number = 10y + x
Conditions = 1
=> A two digit number becomes four seventh
of itself when the position of it's digit are
interchanging
=> 10y + x = 4/7 ( 10x + y)
=> 7 ( 10y + x) = 4 ( 10x + y)
=> 70y + 7x = 40x + 4y
=> 66y = 33x
=> 2y = x ........(1)
Conditions = 2
The difference between the both digit
is = 3
=> x - y = 3 .......(2)
From equation (1) and (2) we get,
put the value of equation (1) in equation (2)
we get,
=> 2y - y = 3
=> y = 3
Put the value of y = 3 in equation (1)
we get,
=> x = 2(3)
=> x = 6
Therefore,
The number are = 10x + y
=> 10(6) + 3 = 63
The number are = 63
Answer:
A2 digit number becomes 47 of itself when the positions of its digit are interchanged The difference between both digits is3 what is the number