Question

A two digit number contains the bigger at ten's place . The product of the digits is 27 and the difference between the two digits is 6 .Find the numver

Answer 1

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Answer 2

Answer:

Required two digit number = 93

Step-by-step explanation:

Given ,

The difference of the two digits is 6.

Let Ten's place digit = x ,

Unit place digit = x-6

The required number = 10x+(x-6)---(1)

Product of the digits = 27

=> x(x-6)=27

=> x²-6x-27=0

Splitting the middle term, we get

=> x² -9x+3x-27=0

=> x(x-9)+3(x-9)=0

=> (x-9)(x+3)=0

=> x-9 = 0 Or x+3=0

=> x = 9 Or x = -3

Now,

Substitute value of x in Equation (1) , we get

if x = 9, the required two digit number is 10x+(x-6)

= 10×9+(9-6)

= 90+3

= 93

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