Math, asked by jaswanth006, 10 months ago

A two digit number exceed the sum of the digits of the number is 18 if the unit place is double the digit in the ten's place. what is the number​

Answers

Answered by suRAJK1594
4

Answer:

24

Step-by-step explanation:

Solution -

Let the tens place digit be x and unit place digit be y.

Therefore, the two digit number is 10x + y.

Given

10x + y = x + y + 18 

9x = 18 

x = 2.

Also given y = 2x = 2 * 2 = 4

Therefore, the two digit number = 10x + y =  10 * 2 + 4  = 24

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