Question

. A two-digit number in which ten's digit is more than the units digit is formed by subtracting 6 from 7 times the sum of the digits. The sum of the digits is equal to five times the difference between the digits.
Find the number.​

Answer 1

Answer:

Let unit digit be X .

Then; according to the question

Tens digit = X+2

Unit digit =X

So,

10(x+2)+x=7[(x+2)+x]

10x+20+x=7(2x+2)

11x+20=14x+14

20–14=14x-11x

6=3x

X=2

So, the unit place digit is 2 and the number be 42.