A two- digit number is 1 more than 5 times the sum of its digits.If 9 is added to the number, its digits are reversed. Find the number.
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Answer:
let the first digit be x
& the last digit is y
then 10x+y=5(x+y)
or 10x-5x+y-5y=0
or 5x=4y
or x=(4/5)y..................(1)
again
10x+y+9=10y+x
or 9y-9x=9
or y-x=1......................(2)
putting the value of x in(1) to (2)
y-(4/5)y=1
or y=5
putting the value of y in (1)
x=(4/5)*5
or x=4
x=4
y=5....................(ans)
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