Question

A two digit number is 1 more than eight times the sum of the digits

Answer 1

Answer:

Step-by-step explanation:

10x + y = 8(x+y) + 1

y = x-3

SYSTEM OF EQUATIONS  

10x + y = 8x + 8y +1  

2x - 7y = 1

-x + y = -3  

2x - 7y = 1

 

-2x + 2y = -6

---------------

-5y = -5  

y = 1  

1 = x-3  

x = 4  

The number is 41.