Question

A two-digit number is 2 more than 8 times the sum of its digits. Find the number if its tens digit is 6 more than its units digit.​

Answer 1

Answer:

Step-by-step explanation:

Let the no. At units place be :- x

Let the no. At tens place be :- y

The no. Becomes :- 10y + x

According to Question,

10y + x = 2 + 8(x + y)

10y + x = 2 + 8x + 8y

2y = 2 + 7x

-7x + 2y - 2 = 0

7x - 2y + 2 = 0..........(i)

And also,

Y = x + 6.......(ii)

Put (ii) in (i)

7x - 2(x + 6) + 2 = 0

7x - 2x - 12 + 2 = 0

5x - 10 = 0

5x = 10

x = 2

Put x = 2 in (ii)

y = x + 6

y = 2 + 6

y = 8

The no. = 10y + x = 82

# Hope it helps.

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Answer 2

Answer:

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