Question

A two digit number is 3 more than 4 times the sum of it's digit. If 18 is added to the number, it's digits are reversed. find the number​

Answer 1

hope it helps you somewhere....

Answer 2

SOLUTION

Let the digit at the units place = x

and tens place = y

Original number = 10y+x

Original number = 10y+xand reverse number= 10x+y

As, it is given that,

=) Two digit number= 4(sum of digits)+3

=) 10y+x= 4(x+y)+3

=) 10y+x= 4x+4y+3

=)4x-x+4y-10y+3=0

=)3x-6y+3= 0

=)x-2y+1=0

=) x-2y= -1..........(1)

Now,

reverse number = original number+18

=) 10x+y= 10y+x+18

=) 9x-9y=18

=) x-y= 2............(2)

On solving (1) &(2), we get

=)-y= -3

=) y= 3

Put this value of y in (1), we get

=) x-2(3)=-1

=) x-6= -1

=)x= -1+6

=)x= 5

Hence,

The original number = 10y+x= 10(3)+5

The original number = 10y+x= 10(3)+5=) 30+5 = 35.

hope it helps ✔️☺️❤️