a two digit number is 3 more than 4 times the sum of its digit if 18 is added to the number its digit are reversed find the number
Answers
Step-by-step explanation:
Let the digits in unit place and 2nd place are x and y
Therefore the number is=10y+x
Now codition, 1
10y+x=3+4(x+y)
10y+x=3+4x+4y
6y=3+3x
2y=1+x
2y=1+y+2 (putting x=y+2)
y=3
And codition 2
10y+x+18=10x+y
9y+18=9x
y+2=x
3+2=x
x=5
Therefore the number is =10*3+5=35
A two digit number is 3 more than 4 times the sum of its digit. If 18 is added to the number its digit are reversed.
The number.
Let the one's digit be R &
Let the ten's digit be M
The original number is 10M + R
- According to the question:
We have,
Two-digit number is 3 more than 4 times the sum of its digits.
→ 10M + R = 4(R + M) + 3
→ 10M + R = 4R + 4M + 3
→ 10M - 4M + R - 4R = 3
→ 6M - 3R = 3..............................(1)
&
if 18 is added from the number, the digits are reversed.
→ 10M + R + 18 = 10R + M
→ 10M - M + R - 10R = -18
→ 9M - 9R = -18
→ 9(M - R) = -18
→ M - R =
→ M - R = -2...............................(2)
- Using Substitution Method:
from equation (2), we get;
⇒ M - R = -2
⇒ M = -2 + R...............................(3)
Putting the value of M in equation (1), we get;
⇒ 6(-2 + R) - 3R = 3
⇒ -12 + 6R - 3R = 3
⇒ -12 + 3R = 3
⇒ 3R = 3 +12
⇒ 3R = 15
⇒
⇒ R = 5
Putting the value of R in equation (3), we get;
⇒ M = -2+ 5
⇒ M = 3
Thus,
The number is 10(3) + 5
The number is 30 + 5 = 35.