A two-digit number is 3 more than 4 times the sum of its digits. If 18 is added to the number, the digits are reversed. Find the number.
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the number is 35
let the digit at one's place be y and that in 10's place be x
so the number is 10x+y
given 10x+y=3+4(x+y) ----- 1
and also given 10x+y+18=10y+x ------2
substituting 1 in 2
gives 3+4(x+y)+18=10y+x
solving the above equation for x, you should get x=2y-7 ------3
now substitute 3 in 1
10(2y-7)+y=3+4(2y-7+y)
solving the above equation for y, you will get 9y=45 which gives y=5 ------4
substitute 4 in 3 and you get x=3
now the number is 10x+y= 10(3) + 5=35
there you go ^_^
let the digit at one's place be y and that in 10's place be x
so the number is 10x+y
given 10x+y=3+4(x+y) ----- 1
and also given 10x+y+18=10y+x ------2
substituting 1 in 2
gives 3+4(x+y)+18=10y+x
solving the above equation for x, you should get x=2y-7 ------3
now substitute 3 in 1
10(2y-7)+y=3+4(2y-7+y)
solving the above equation for y, you will get 9y=45 which gives y=5 ------4
substitute 4 in 3 and you get x=3
now the number is 10x+y= 10(3) + 5=35
there you go ^_^
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