Question

a two digit number is 3 more than 4 times the sum of its digits if 18 is added to the number its digits are reversed find the number​

Answer 1

Let x be units digit and y be the 10s digit

10y+x = 4(x+y)

10y + x = 4x +4y

6y-3x = 0

2y - x = 0 ————-(1)

When 18 is added to the number

10y + x +18 = 10x + y

Simplify

9y - 9x = -18

y - x = - 2

y = x - 2 —————-(2)

Substitute in equation #1

2(x-2) - x = 0

2x - 4 - x=0

x = 4

Substitute in equation#2

y = 2

There for the number is

2 x 10 + 4 = 24

hope it will help you

Answer 2

Answer:

Step-by-step explanation:

Let the digits be x and y

Thus, number=10x+y

Now,

(10x+y) - 4(x+y)= 3.....(i)

and

(10x+y)+ 18=10y+x.....(ii)

Solving

(i)10x+y-4x-4y=3

or,6x-3y=3or,2x-y=1...

(1)Solving

(ii)10x+y-10y-x=-18 or

, 9y-9x=18

or,y-x=2.

(1)+(2)

2x-y+y-x=1+2

or

x=3

Thus,

y=x+2

(from (2))y=5

Therefore the number=

10x+y=10x3+5=35