A two digit number is 3 more than 4 times the sum of its digit. If 18 is added to this number , the sum is equal to the number obtained by interchanging the digit . Find the number.
Answers
Answer:
Step-by-step explanation:
Let the ten's digit of the number be x and the unit's digit be y.
Original number =10x+y
Reversed number = 10y + x
Sum of the digits = x+y
According to the question
10x + y=4(x+y)+3
10x +y =4x +4y +3
6x -3y =3
2x -y =1
Again
18 + 10x +y =10y+x
9x -9y = -18
x-y= -2
Solving the two equations we get
x=3 and y = 5
Therefore the number is 35.
Answer:
53
Step-by-step explanation:
Let tens digit be = x
then , units digit = y
number = 10x + y
reversed number = 10y + x
Given ,
10y + x = 4(x+y) + 3
10y + x = 4x + 4y + 3
10y - 4y + x - 4x = 3
6y - 3x = 3
2(2y - x) = 3
2y - x = 3--------1
second part of the question says -
(10y + x + 18) = 10x + y
10y - y + x - 10x = 18
9y - 9x = 18
9 ( y - x ) = 18
y - x = 18 / 9
y - x = 2---------2
Now we should add the equation 1 and 2
2y-x+x-y=1+2
2y-y=3
y=3........(3)
put equation (3) in equation (2)
x-y=2
x-3=2
x=2+3
x=5
hence, the number will be
10x+y
10*5+3
50+3
53
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