Question

A two digit
number is
3 more than
4 times
the The sum
of its digit.
18 is added to the number
the
digits are reversed. Find the
number.
​

Answer 1

Answer:

13

Step-by-step explanation:

Let the two digits be a and b

'ab' (10a + b) + 3 = 4(a+b)

ab + 18 = ba

10a + b + 18 = 10b + a

10a - a + 18 = 10b - b

9a + 18 = 9b

9(a+2)=9(b)

a+2 = b

a+2+b = 2b

a+b = 2b - 2

a+2 = b

a= b-2

(10a + b) + 3 = 4(a+b)

10(b-2)+b + 3 = 4(2b-2)

10b - 20 + b + 3 = 8b -8

11b - 17 = 8b - 8

11b - 8b = 17-8

3b = 9

b = 9/3 = 3

a = b - 2

a = 3 - 2

a = 1

ab = 13