a two digit number is 36 more than the number obtained by reversing the digits of difference between 10 digit and unit digit is 4
find the number
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Let the number be 10a+b
where a is tens digit and b is unit digit.
Given,
10a+b = 10b+a + 36
= 10a - a +b - 10b = 36
= 9a - 9b = 36
= [a - b = 4]
Now
difference is 4 as given.
then , number is 62
62= 26+36.
where a is tens digit and b is unit digit.
Given,
10a+b = 10b+a + 36
= 10a - a +b - 10b = 36
= 9a - 9b = 36
= [a - b = 4]
Now
difference is 4 as given.
then , number is 62
62= 26+36.
yuvrajkj:
you sure the question is complete?
the question i encountered some time ago said that ten's digit is twice the unit digit
I checked again
wait a min
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