a two digit number is 3more than 4 times the sum of digits if 18 is added to the number the digit are reversed find the number
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Let the number be 10x + y zuch that x is the digit at tens place and y is the digit at ones place....
According to the given conditions,
4(x+y)+3 = 10x + y
4x + 4y + 3 = 10 x + y
10x - 4x = 4y - y +3
6x - 3y = 3
Dividing by 3
2x-y=1..........(i)
10x + y +18=10y + x
9x - 9y = -2
Dividing by 9
x-y = -1....... (ii)
Solving i and ii
2x - y = 1
x - y = -1
....................
x = 2
Then y = 3
Therefore the number is 10x + y = 10*2 + 3 = 23
Hope this helps....
Plz mark as brainliest....
According to the given conditions,
4(x+y)+3 = 10x + y
4x + 4y + 3 = 10 x + y
10x - 4x = 4y - y +3
6x - 3y = 3
Dividing by 3
2x-y=1..........(i)
10x + y +18=10y + x
9x - 9y = -2
Dividing by 9
x-y = -1....... (ii)
Solving i and ii
2x - y = 1
x - y = -1
....................
x = 2
Then y = 3
Therefore the number is 10x + y = 10*2 + 3 = 23
Hope this helps....
Plz mark as brainliest....
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