Question

A two-digit number is 4/7 of the number formed by reversing its digits. when the number is increased by 2 times the sum of its digit, it becomes 54. find the number.

Answer 1

Answer:

Let the digit in the ones place be x and tens place be y

Hence the two digit number =10y+x

Given that the two digit number =4 times sum of its digits

According to the question,

⇒  10y+x=4(x+y)

⇒  10y+x=4x+4y

⇒  3x−6y=0

⇒  x=2y                   ------- ( 1 )

It is also given that the two digit number =2 times product of its digits

⇒  10y+x=2xy

Divide by xy both the sides, we get

⇒  x10+y1=2

Put x=2y from (1), we get

⇒  2y10+y1=2

⇒  y5+y1=2

⇒  y6=2

∴  y=3

⇒  x=2y=2(3)=6

⇒  The two digit number =(10y+x)=10(3)+6=36

Answer 2

Answer:

36

Step-by-step explanation: