Question

A two digit number is 4 digit the sum of its digit and twice the product of its digit, find the number

Answer 1

Answer:

Let the required Digit be 10x + y

Given-

• A two digit number is 4 digit the sum of its digit.
• and, twice the product of its digit

According to the Question -

10x + y = 4(x + y)

Now, we'll open the bracket -

10x + y = 4x + y

→ 10x + y - 4x - y = 0

→ 6x - 3y = 0

→ 2x - y = 0 (eqⁿ 1)

10x + y = 2xy (eqⁿ 2)

Now, by putting the value of y in equation 2 from 1 -

4x² - 12x = 0

→ 4x (x-3) = 0

→ x(x-3) = 0

→ x - 3 = 0

→ x = 3

Putting value of x in 2x = y

2x = y

→ 2(3) = y

→ 6 = y

Now, by putting the value of x and y in 10x + y, we'll get the required number -

10x + y

→ 10(3) + 6

→ 30 + 6

→ 36

Answer 2

Answer:

Number is 36

Step-by-step explanation:

A two digit number is 4 times the sum of it's digits.

Assume that the ten's digit be x one's digit be y.

As per given condition,

→ 10x + y = 4(x+y)

→ 10x + y = 4x + 4y

→ 10x - 4x = 4y - y

→ 6x = 3y

→ 2x = y ..................(1)

Also given that, two digit number is twice the product of its digit.

→ 10x + y = 2xy

Substitute value of equation (1) in above equation,

→ 10x + 2x = 2x(2x)

→ 12x = 4x²

→ 3 = x

Substitute value of x in (1)

→ y = 2(3)

→ y = 6

Hence, the number is 10(3)+6 i.e. 36.