a two digit number is 4 more than 6 times the sum of digits. write a linear equation in two variables to represent this statement
Answers
Answered by
8
Hey
Let the tens digit be x .
unit digit be y .
So , number = 10x + y
Now sum of digits = x + y .
A/q ,
10x + y = 6 ( x + y ) + 4
Here is the equation in two variable for this statement .
thanks :)
Keep loving , keeo smiling !!
Let the tens digit be x .
unit digit be y .
So , number = 10x + y
Now sum of digits = x + y .
A/q ,
10x + y = 6 ( x + y ) + 4
Here is the equation in two variable for this statement .
thanks :)
Keep loving , keeo smiling !!
Rishan11:
Answer wrong hai
Answered by
18
Hey!!
HERE IS YOUR ANSWER,,
Unit place = y
Ten's place = x
Original no. = 10x + y
sum of the digits = x + y
Given that :- Two digit number is 4 more than 6 times the sum of digits.
so,
10x + y = 6(x + y ) + 4
10x + y = 6x + 6y + 4
10x - 6x + y - 6y - 4 = 0
4x - 5y - 4 = 0
according to the statement this is the linear equation in two variable.
HOPE IT HELPS....
THANKS..
HERE IS YOUR ANSWER,,
Unit place = y
Ten's place = x
Original no. = 10x + y
sum of the digits = x + y
Given that :- Two digit number is 4 more than 6 times the sum of digits.
so,
10x + y = 6(x + y ) + 4
10x + y = 6x + 6y + 4
10x - 6x + y - 6y - 4 = 0
4x - 5y - 4 = 0
according to the statement this is the linear equation in two variable.
HOPE IT HELPS....
THANKS..
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