A two digit number is 4 more than 6 times the sum of its digits. If 18 is
subtracted from the number, the digits are reversed. Find the number.
[By the method of elimination only)
Answers
Answer:
Slkssjhksososhvrkssosicdn sorry do not know
Explanation:
A two digit number =4
The 2digit number is more than the 6times the sum of the digits
Let X=ones digits
let y=two digit
X+10y=6(X+y)+4
x+10y=6x+6y+4
10y-6y=10x-x+4
4y=9x+4
and, from "if 18 is subtracted from the number,the digits are reversed.find the number"
x+10y -18 = y+10x
10y -18 = y+9x
9y -18 = 9x
y -2 = x
substitute on the value
4y = 5x+4
4y = 5x+44y = 5(y-2)+4
4y = 5x+44y = 5(y-2)+44y = 5y-10+4
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-6
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:4y = 5x+4
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:4y = 5x+44(6) = 5x+4
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:4y = 5x+44(6) = 5x+424 = 5x+4
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:4y = 5x+44(6) = 5x+424 = 5x+420 = 5x
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:4y = 5x+44(6) = 5x+424 = 5x+420 = 5x4 = x
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:4y = 5x+44(6) = 5x+424 = 5x+420 = 5x4 = x.
4y = 5x+44y = 5(y-2)+44y = 5y-10+44y = 5y-64y+6 = 5y6 = y.substitute above into:4y = 5x+44(6) = 5x+424 = 5x+420 = 5x4 = x.The number is 64
.