A two-digit number is 4 more than 6 times the sum of its digits. If 18 is subtracted from the number, the digits are reversed. Find the number.
Answers
Given : A two-digit number is 4 more than 6 times the sum of its digits. If 18 is subtracted from the number, the digits are reversed.
Solution:
Let the digit in the unit's place be x and the digit at the tens place be y.
Number = 10y + x
The number obtained by reversing the order of the digits is = 10x + y
ATQ :
Condition : 1
10y + x = 6(x + y) + 4
10y + x = 6x + 6y + 4
10y + x - 6x - 6y = 4
-5x + 4y = 4
5x - 4y = - 4 ……………(1)
Condition : 2
(10y + x) - 18 = 10x + y
10y + x - 10x - y = 18
- 9x + 9y = 18
-9(x - y) = 18
x - y = -18/9
x - y = - 2 …………..(2)
On multiplying equation (2) by 4 :
4x - 4y = - 8 …………..(3)
On Subtracting equation (3) from equation (1), we obtain :
5x - 4y = - 4
4x - 4y = - 8
(-) (+) (+)
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x = 4
On putting x = 4 in eq (1) we obtain :
5x - 4y = - 4
5 (4) - 4y = - 4
20 - 4y = - 4
-4y = - 4 - 20
-4y = - 24
y = 24/4
y = 6
Now, Number = 10y + x = 10 × 6 + 4 = 60 + 4 = 64
Hence, the number is 64.
Hope this answer will help you…
Some more questions from this chapter :
A two-digit number is 4 times the sum of its digits. If 18 is added to the number, the digits are reversed. Find the number.
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A two-digit number is 3 more than 4 times the sum of its digits. If 18 is added to the number, the digits are reversed. Find the number.
https://brainly.in/question/17181140
Answer:
Given:
⇏ A two-digit number is 4 more than 6 times the sum of its digits. If 18 is subtracted from the number, the digits are reversed.
Find:
⇏ Find the number.
According to the question:
⇏ Let us assume 'x' as ones digit and 'y' as tens digit.
Calculations:
⇏
⇏
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Subtracting 18 with the number:
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⇏
⇏
Adding values from above equations:
⇏
⇏
⇏
⇏
⇏
⇏
Adding values from above equations:
⇏
⇏
⇏
⇏
⇏
Therefore, value of xy = 64 and 64 is the number.