A two digit number is 4 more than 6 times
the sum of its digit. If 8 is subtracted from
the number the digit get reversed. Find the
number.
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Answer:
Let x= ones digit and y=tens digit
According to the question ,
∴x+10y=6(x+y)+4
⇒10y=6x+6y+4−x
⇒4y=5x+4
And , from if 18 is substracted from the number , the digits are reversed ,
∴x+10y−18=y+10x
⇒10y−18=y+9x
⇒9y−18=9x
⇒y−2=x
Substitute x value into :
4y=5x+4
4y=5(y−2)+4
4y=5y−6
y=6
Substitute y into :
∴y−2=x
⇒6−2=x
⇒4=x
∴ The number is 64.
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