Question

a two digit number is 4 more than six times the sum of its digits. if 18 is subtracted from the number the digits are reversed find the number

Answer 1

Answer:

64

Step-by-step explanation:

Let x be ones digit and y be tens digit

ACCORDING TO FIRST PART OF THE QUESTION,

x + 10y = 6(x+y)+4

x + 10y = 6x+6y+4

10y = 5x+6y+4

4y = 5x+4-------------------(1)

.

AND, ACCORDING TO SECOND PART OF THE QUESTION,

x+10y -18 = y+10x

10y -18 = y+9x

9y -18 = 9x

y -2 = x-----------------(2)

.

substitute the value of x in(1) from (2):

4y = 5x+4

4y = 5(y-2)+4

4y = 5y-10+4

4y = 5y-6

4y+6 = 5y

6 = y

.

substitute value of y in (2)

y -2 = x

6-2=4

.

y=6 and x=4

The number is 64

Answer 2

Answer:

Refer to the attachment........... ☺