A two-digit number is 4 times the sum of its digits. If 18 is added to the number, the digits
are reversed. Find the number.
[CBSE 2001C)
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Let the digits be x and y
Then the two-digit number is 10x + y
Given that: 10x + y = 4 (x + y)
10x + y = 4x + 4y
6x = 3y
y = 2x --------------- 1
And 10x + y + 18 = 10y + x
Or 9y – 9x =
18 ---------------- 2
Substitute the value of y in eqn 2
18x – 9x = 18
9x = 18
x = 2
Therefore y = 2x =
2*2 = 4
And the number is 10x + y = 10*2 + 4 = 24
Answer: The two-digit number is 24.
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