A two digit number is 4 times the sum of its digits. If 18 is added to the number, the digits are reverse. Find the number.
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let the number be 10x+y
and the digits be x&y
therefore, according to the condition,
10x+y=4(x+y)
10x+y=4x+4y
10x-4x=4y-y
6x=3y (/3)
2x=y.............................1
according to 2nd condition,
18+10x+y=10y+x
10x-x+y-10y=-18
9x-9y=-18.........................2
sub 1 in 2
9x-9(2x)=-18
9x-18x=-18 (/9)
x-2x=-2
x=2
y=2x=2(2)=4
number=10(x)+y=10(2)+4
20+4=24
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and the digits be x&y
therefore, according to the condition,
10x+y=4(x+y)
10x+y=4x+4y
10x-4x=4y-y
6x=3y (/3)
2x=y.............................1
according to 2nd condition,
18+10x+y=10y+x
10x-x+y-10y=-18
9x-9y=-18.........................2
sub 1 in 2
9x-9(2x)=-18
9x-18x=-18 (/9)
x-2x=-2
x=2
y=2x=2(2)=4
number=10(x)+y=10(2)+4
20+4=24
sorry for late answering
please mark my answer as brainliest
hope it helps...........please feel free to ask doubts
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